Describe the van der Waals equation and explain why it corrects the ideal gas law for real gases.

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Multiple Choice

Describe the van der Waals equation and explain why it corrects the ideal gas law for real gases.

Explanation:
Real gases don’t follow the ideal gas law exactly because molecules have finite size and exert intermolecular attractions. The van der Waals approach introduces corrections to account for these effects: the pressure term is increased by a(n/V)^2 to reflect the reduction in effective pressure due to attractions, and the volume term is reduced to V − nb to account for the space taken up by the molecules themselves. Putting these together gives (P + a(n/V)^2)(V − nb) = nRT. If you solve for P, you get P = nRT/(V − nb) − a(n/V)^2, showing how the first part drives pressure up as free volume decreases, while the second part subtracts pressure due to attractive forces. The other forms either misuse the dependence on n and V, flip the sign of the correction, or revert to the ideal gas law entirely, which is why this equation is the correct one.

Real gases don’t follow the ideal gas law exactly because molecules have finite size and exert intermolecular attractions. The van der Waals approach introduces corrections to account for these effects: the pressure term is increased by a(n/V)^2 to reflect the reduction in effective pressure due to attractions, and the volume term is reduced to V − nb to account for the space taken up by the molecules themselves. Putting these together gives (P + a(n/V)^2)(V − nb) = nRT. If you solve for P, you get P = nRT/(V − nb) − a(n/V)^2, showing how the first part drives pressure up as free volume decreases, while the second part subtracts pressure due to attractive forces.

The other forms either misuse the dependence on n and V, flip the sign of the correction, or revert to the ideal gas law entirely, which is why this equation is the correct one.

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